A mass of 2 kg tied to a string 1 m length is rotate in a verticle circle with a uniform speed of `4 m//s`. The tension in the string will be 52 N, when the mass is at `(g=10 m//s^(2))`

Options

A. bottom
B. highest point
C. midway
D. horizontal position

Answer

A

Explanation

`T=(mv^(2))/(r)+m g cos theta `
`therefore mg cos theta =T-(mv^(2))/(r)`
`=52-(2xx16)/(1)`
` cos theta =(20)/(mg)=(20)/(2xx10)=1`
`cos theta =1`
`theta =cos^(-1) (0)=0`.