A bucket full of water is revolved in vertical circle of radius 2 m . What should be the maximum time-period of revolution so that the water doesn't fall off the bucket

Options

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Answer

C

Explanation

Minimum angular velocity `omega _(min)=sqrt(g//R)`
`thereforeT_(max)=(2pi)/(omega_(min))=2pisqrt((R)/(g))=2pisqrt((2)/(10))`
`=2sqrt2=3 s`