An automobile engine starting from rest is given an angular acceleration of `20 rad //s ^(2)` for 10 s .Find the angle turned during this period

Options

A. `10 rad`
B. `100 rad`
C. ` 1000 rad`
D. `0.1 rad`

Answer

C

Explanation

` alpha =(omega_(2)-omega_(1))/(t)" " thereforew_(2)=200 rad//sec.`
`n_(2)=(omega_(2))/(2 pi)=(200)/(2pi)=(100)/(pi)`
`N=(n_(1)+n_(2))/(2)xxt=(50)/(pi)xx10=(500)/(pi)`
` therefore theta =(500)/(pi)xx2pi=1000 rad`