A cycle wheel of radius 0.4 m completes one revolution in one second then the acceleration of a point on the cycle wheel will be

Options

A. `0.4 pi m//s^(2)`
B. `0.8 pi m//s^(2)`
C. `0.4 pi m//s^(2)`
D. `1.6 pi ^(2) m//s^(2)`

Answer

D

Explanation

`A = r omega ^(2)`
`=r 4pi^(2)n^(2)=0.4xx4xxpi^(2)xx1=1.6 pi^(2)`