A car is moving with speed `30m//sec` on a circular path of radius 500 m . Its speed is increasing at the rate of , `2m//sec^(2)`, What is the acceleration of the car

Options

A. `9.8 m//s^(2)`
B. `1.8 m//s^(2)`
C. `2 m//s^(2)`
D. `2.7 m//s^(2)`

Answer

D

Explanation

`a_(r)=V^(2)/(r)=(30xx30)/(500)=(9)/(5)=1.8,a_(T)=2 m//s^(2)`
`a_(R)=sqrt(a_(r)^(2)+a_(T)^(2))`
`=sqrt(4+3.24)=sqrt(7.24)=2.7 m//s^(2)`.