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A particle performing circular motion wi...

A particle performing circular motion with its diameter d and velocity v. Then the angular displacement of the particle in time t is

A

`(vt)/(d)`

B

`(2vt)/(d)`

C

`(vt)/(2d)`

D

`(d)/(vt)`

Text Solution

Verified by Experts

The correct Answer is:
B
`theta= omegat`
`=(V)/(r)t=(2V)/(2r)t`
`theta=(2Vt)/(d)`.
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