A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration `a_(c)` is varying with time t as `a_(c) = k^(2)rt^(2)`, where k is a constant. The power delivered to the particle by the forces acting on it is :

Options

A. ` m^(2)K^(2)r^(2)t^(2)`
B. `mK^(2)r^(2)t^(2)`
C. `mK^(2)rt^(2)`
D. `mKr^(2)t^(2)`

Answer

B

Explanation

`F=ma=mK^(2)rt^(2)`
`P=(w)/(t)=(F.s)/(t)=(mK^(2)rt^(2))/(t)r`
`=mK^(2)r^(2)t`