A particle moves along a circle of radiu...

A particle moves along a circle of radius R with a constant angular speed `omega`. Its displacement (only magnitude) in time t will be

`((v)/(D))-t`

`(vt)/(2D)`

`(2vt)/(D)`

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The correct Answer is:

`theta = omega t=(v)/(r)t=(2v)/(2r)t=(2v)/(D)t`

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