Mass remaining the same, if radius of the earth is doubled, acceleration due to gravity on the surface of the earth would be (g is present value)

Options

A. 2 g
B. g/2
C. g/4
D. 4 g

Answer

c

Explanation

`R_(2)=2R_(1)`
`(g_(2))/(g_(1))=((R_(1))/(R_(2)))^(2)=((R)/(2R))^(2)=(1)/(4)`
`g_(2)=(g)/(4)`