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The earth of mass 6xx10^(24)kg revolves ...

The earth of mass `6xx10^(24)kg` revolves round the sun with angular velocity `3xx10^(-7)"rad/s"` in a circular orbit of radius `1.5xx10^(8)km.`` Then the force exerted by the sun on the earth in newtons, is

A

`18xx10^(25)`

B

`36xx10^(18)`

C

`36xx10^(21)`

D

`81xx10^(21)`

Text Solution

Verified by Experts

The correct Answer is:
d
`F=mr omega^(2)`
`=6xx10^(24)xx1.5xx10^(11)xx9xx10^(-4)`
`=81xx10^(21)`
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