Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Options

A. `sqrt((Gm)/(r))`
B. `sqrt((Gm)/(2r))`
C. `sqrt((Gm)/(4r))`
D. `sqrt((Gm)/(8r))`

Answer

c

Explanation

`"G.F. = C.F."`
`(Gm^(2))/(4r^(2))=(mv^(2))/(r)`
`therefore" "v^(2)=(Gm)/(4r)`
`v=sqrt((Gm)/(4r))`