The mass of a planet is `(1//10)^("th")` that of earth and its diameter is half that of earth the acceleration due to gravity is

Options

A. `1.96m//s^(2)`
B. `3.92m//s^(2)`
C. `9.8m//s^(2)`
D. `19.6m//s^(2)`

Answer

b

Explanation

`g=(GM)/(R^(2))" and "g'(GM')/(R'^(2))`
`therefore" "(g')/(g)=(M')/(M)xx(R^(2))/(R'^(2))`
`=(1)/(10)xx(2)^(2)=(2)/(5)`