Home
Class 12
PHYSICS
The mass of a planet is (1//10)^("th") t...

The mass of a planet is `(1//10)^("th")` that of earth and its diameter is half that of earth the acceleration due to gravity is

A

`1.96m//s^(2)`

B

`3.92m//s^(2)`

C

`9.8m//s^(2)`

D

`19.6m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
b

`g=(GM)/(R^(2))" and "g'(GM')/(R'^(2))`
`therefore" "(g')/(g)=(M')/(M)xx(R^(2))/(R'^(2))`
`=(1)/(10)xx(2)^(2)=(2)/(5)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROSTATICS

    NIKITA PUBLICATION|Exercise Multiple Choice Questions|458 Videos
  • INTERFERENCE AND DIFFRACTION

    NIKITA PUBLICATION|Exercise MULTPLE CHOICE QUESTIONS|333 Videos

Similar Questions

Explore conceptually related problems

Acceleration due to gravity of earth

The mass of a planet is 6 times the mass of earth and its radius is 3 times that of the earth . Considering acceleration due to gravity on earth to be 9.8m//s^2 , calculate the value of g on the other planet.

Knowledge Check

  • At the centre of earth the acceleration due to gravity is

    A
    infinite
    B
    zero
    C
    `9.8 ms^(-2)`
    D
    all of these
  • If the mass of a planet is 10% less than that of the earth and the radius is 20% greater than that of the earth, the acceleration due to gravity on the planet will be

    A
    `5/8` times that on the surface of the earth
    B
    `3/4` times that on the surface of the earth
    C
    `1/2` times that on the surface of the earth
    D
    `9/10` times that on the surface of the earth
  • If the density of the planet is double that of the earth and the radius 1.5 times that of the earth, the acceleration due to gravity on the planet is

    A
    4/3 times that on the surface of the earth
    B
    3 times that on the surface of the earth
    C
    3/4 times that on the surface of the earth
    D
    6 times that on the surface of the earth
  • Similar Questions

    Explore conceptually related problems

    The mass of Saturn is 95.22 times that of the Earth and its radius is 9.47 times of the Earth. The acceleration due to gravity on the surface of the Earth is 9.8 m//s^(2) . Find the acceleration due to gravity on the surface of Saturn.

    The radius of a planet is 1/4 of earth’s radius and its acceleration due to gravity is double that of earth’s acceleration due to gravity. How many times will the escape velocity at the planet’s surface be as compared to its value on earth’s surface

    The value of acceleration due to gravity of earth :

    If the mass of earth is eighty times the mass of a planet and diameter of the planet is one fourth that of earth, then acceleration due to gravity on the planet would be

    The mass of a planet and its diameter are three times those of earth's. Then the acceleration due to gravity on the surface of the planet is : (g =9.8 ms^(-2))