Assuming that the Earth is a sphere of radius `R`. At what altiude will the value of acceleration due to gravity be half its value at the surface of the Earth?

Options

A. `3R`
B. `R//sqrt2`
C. `(sqrt2+1)R`
D. `(sqrt2-1)R`

Answer

d

Explanation

`(g')/(g)=(R^(2))/((R+h)^(2))" or "(1)/(2)=(R^(2))/((R+h)^(2))`
`h=(sqrt2-1)R`