Mass remaining the same, if radius of the earth is doubled, acceleration due to gravity on the surface of the earth would be (g is present value)

Options

A. 2g
B. g/2
C. g/4
D. 4g

Answer

c

Explanation

`(g_(d))/(d)=((R_(1))/(R_(2)))^(2)=((R)/(2R))^(2)=(1)/(4)`
`g_(2)=(g_(1))/(4)=(g)/(4)`.