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The earth is a solid sphere of radius 6400 km, the value of acceleration due to gravity at a height 800 km above the surface of the earth is

A

`5.35m//s^(2)`

B

`6.35m//s^(2)`

C

`7.35m//s^(2)`

D

`8.35m//s^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the acceleration due to gravity at a height of 800 km above the Earth's surface, we can use the formula for gravitational acceleration at a height \( h \) above the Earth's surface: \[ g' = g \left( \frac{R}{R + h} \right)^2 \] where: - \( g' \) is the acceleration due to gravity at height \( h \), - \( g \) is the acceleration due to gravity at the Earth's surface (approximately \( 9.8 \, \text{m/s}^2 \)), - \( R \) is the radius of the Earth, - \( h \) is the height above the Earth's surface. ### Step 1: Convert the radius and height to meters Given: - Radius of the Earth, \( R = 6400 \, \text{km} = 6400 \times 10^3 \, \text{m} \) - Height above the surface, \( h = 800 \, \text{km} = 800 \times 10^3 \, \text{m} \) ### Step 2: Substitute the values into the formula Now we substitute the values into the formula: \[ g' = 9.8 \left( \frac{6400 \times 10^3}{6400 \times 10^3 + 800 \times 10^3} \right)^2 \] ### Step 3: Simplify the expression Now simplify the expression inside the parentheses: \[ g' = 9.8 \left( \frac{6400 \times 10^3}{7200 \times 10^3} \right)^2 \] \[ g' = 9.8 \left( \frac{6400}{7200} \right)^2 \] ### Step 4: Calculate the fraction Now calculate \( \frac{6400}{7200} \): \[ \frac{6400}{7200} = \frac{64}{72} = \frac{8}{9} \] ### Step 5: Substitute back into the equation Now substitute back into the equation: \[ g' = 9.8 \left( \frac{8}{9} \right)^2 \] ### Step 6: Calculate \( \left( \frac{8}{9} \right)^2 \) Calculate \( \left( \frac{8}{9} \right)^2 \): \[ \left( \frac{8}{9} \right)^2 = \frac{64}{81} \] ### Step 7: Final calculation Now substitute this back into the equation for \( g' \): \[ g' = 9.8 \times \frac{64}{81} \] Calculating this gives: \[ g' = \frac{9.8 \times 64}{81} \approx \frac{627.2}{81} \approx 7.75 \, \text{m/s}^2 \] ### Conclusion Thus, the acceleration due to gravity at a height of 800 km above the Earth's surface is approximately \( 7.75 \, \text{m/s}^2 \).

To find the acceleration due to gravity at a height of 800 km above the Earth's surface, we can use the formula for gravitational acceleration at a height \( h \) above the Earth's surface: \[ g' = g \left( \frac{R}{R + h} \right)^2 \] where: - \( g' \) is the acceleration due to gravity at height \( h \), ...
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