The gravitational force between two objects is proportional to `1//R` (and not as `1//R^(2)`) where `R` is separation between them, then a particle in circular orbit under such a force would have its orbital speed `v` proportional to

Options

A. `1//R^(2)`
B. `R^(0)`
C. `R^(1)`
D. `1//R`

Answer

b

Explanation

`F=(K)/(R)=(Mv^(2))/(R)" hence "v prop R^(0)`