A satelite revolves around a planet in an elliptical orbit. Its maximum and minimum distances from the planet are `1.5xx10^(7)` m and `0.5xx10^(7)` m respectively. If the speed of the satellite at the farthest point be `5xx10^(3)` m/s, calculate the speed at the nearest point.

Options

A. 28 km/s
B. 15 km/s
C. 5/3 km/s
D. 3.5 km/s

Answer

b

Explanation

`V_("max")r_("min")=V_("min" r_("max")`
`V_("max")=(V_("min")r_("max"))/(r_("min"))=(5xx1.5xx10^(7))/(0.5xx10^(7))`
`=15km//s.`