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Asatellite is launched into a circular orbit of radius R around the earth. A second satellite is launched into an orbit of radius (1.04) R. Then the period of the second satellite is large than that of the first one by approximately

A

`1.5%`

B

`1.0%`

C

`6.0%`

D

`3.0%`

Text Solution

Verified by Experts

The correct Answer is:
c

`T_(1)^(2) prop R_(1)^(3) therefore (T_(2))/(T_(1))=[(R_(2))/(R_(1))]^(3//2)=(1.01)^(3//2)`
`(DeltaT)/(T)=(3)/(2)(DeltaR)/(R)`
`therefore" "(T_(2)-T_(1))/(T_(1))=(3)/(2)xx4=6`
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