The time period of a satellite of earth is 5 hours. If the separation between the centre of earth and the satellite is increased to 4 times the previous value, the new time period will become-

Options

A. 10 h
B. 80 h
C. 40 h
D. 20 h

Answer

c

Explanation

`(T_(2))/(T_(1))=((r_(2))/(r_(1)))^(3//2)=(4)^(3//2)=8`
`T_(2)=8T`
`=8xx5=40h.`