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The figure shows the motion of a planet around the sun in an elliptical orbit with the sun at one focus. The shaded area SAB is twice that of SCD. If `t_(1) and t_(2)` are the times taken by the planet to move from A to B and C to D respectively, then

A

`t_(1)=t_(2)`

B

`t_(2)=2t_(1)`

C

`t_(1)=2t_(2)`

D

none

Text Solution

Verified by Experts

The correct Answer is:
c

`(t_(1))/(t_(2))=(A_(1))/(A_(2))=(2A_(2))/(A_(2))=2`
`t_(1)=2t_(2)`.
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