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From the figure, the gravitational poten...

From the figure, the gravitational potential at '0' due to three point masses is

A

`(Gm)/(l)(2+(1)/(sqrt2))`

B

`(Gm)/(l)(sqrt+(1)/(2))`

C

`(3Gm)/(l)`

D

`(2Gm)/(l)`

Text Solution

Verified by Experts

The correct Answer is:
a

`v=v_(1)+v_(2)+v_(3)`
`=-(Gm)/(l)-(Gm)/(l)-(Gm)/(sqrt2l)`
`=-(Gm)/(l)[1+1+(1)/(sqrt2)]=-(Gm)/(l)[2+(1)/(sqrt2)]`.
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