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Three particles each of mass m are kept ...

Three particles each of mass `m` are kept at vertices of an equilateral triangle of side L. The gravitational field at centre due to these particle is

A

zero

B

`(Gm^(2))/(a^(2))`

C

`(2Gm^(2))/(a^(2))`

D

`(3Gm^(2))/(a^(2))`

Text Solution

Verified by Experts

The correct Answer is:
a

`V=-(GM)/(r//2)-(GM)/(r//2)=-(4GM)/(r)`
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