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The work done to remove a body of mass 1...

The work done to remove a body of mass 10 kg from the surface of the earth of radius 'R' and 'g' acceleration due to gravity to value 6400 km and `10m//s^(2)` respectively to infinity is

A

`1.28J`

B

`6.4xx10^(8)J`

C

`1.28xx10^(8)J`

D

`3.2xx10^(8)J`

Text Solution

Verified by Experts

The correct Answer is:
b

`"P E "=("GMm")/(R)=(gR^(2)m)/(R)`
= mgR
`=10xx10xx6.4xx10^(6)=6.4xx10^(8)J.`
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