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Escape velocity of a body from the surfa...

Escape velocity of a body from the surface of earth is 11.2km/sec. from the earth surface. If the mass of earth becomes double of its present mass and radius becomes half of its present radius then escape velocity will become

A

`5.6km//s`

B

`11.2km//s`

C

`22.4km//s`

D

`44.8km//s`

Text Solution

Verified by Experts

The correct Answer is:
c
`v_(e)=sqrt(2gR)=sqrt(("2GM")/(R))`
`v'_(e)=sqrt((2G(2M))/(R//2))=2sqrt((2GM)/(R))=2v_(e)`
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