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The escape velocity of the earth is 11.2...

The escape velocity of the earth is 11.2 km/s. For a planet whose mass and radius are twice those of the earth, the escape velocity will be

A

44.8 km/s

B

22.4 km/s

C

11.2 km/s

D

2.8 km/s

Text Solution

Verified by Experts

The correct Answer is:
c
`v_(e)=sqrt((2MC)/(R))`
`v'_(e)=sqrt(("2M'G")/(R'))=sqrt((2(2M)G)/(2R))=sqrt((2MG)/(R))=v_(e)`
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