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The escape velocity corresponding to a p...

The escape velocity corresponding to a planet of mass `M` and radius `R` is `50 km s^(-1)`. If the planet's mass and radius were `4M` and `R`, respectively, then the corresponding escape velocity would be

A

24 km/s

B

3 km/s

C

6 km/s

D

4 km/s

Text Solution

Verified by Experts

The correct Answer is:
b

`(v_(e_(2)))/(v_(e_(1)))=(R_(2))/(R_(1))sqrt((rho_(2))/(rho_(1)))=(1)/(4)`
`v_(e_(2))=(v_(e_(1)))/(4)=(12)/(4)=3km//s.`
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