Home
Class 12
PHYSICS
The escape velocity from the surface of ...

The escape velocity from the surface of the earth of radius `R` and density `rho`

A

`sqrt(2pi g rhoR)`

B

`2Rsqrt((2Gpirho)/(3))`

C

`sqrt(4piG rho R)`

D

`sqrt((4)/(3)piGrhoR)`

Text Solution

Verified by Experts

The correct Answer is:
b
`v_(e)=sqrt((2GM)/(R))=sqrt((2Ge)/(R)(4pi)/(3)R^(3))=2Rsqrt((2Gepi)/(3)).`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    NIKITA PUBLICATION|Exercise Multiple Choice Questions|458 Videos

  • INTERFERENCE AND DIFFRACTION

    NIKITA PUBLICATION|Exercise MULTPLE CHOICE QUESTIONS|333 Videos

Similar Questions

Explore conceptually related problems

The escape velocity of a body from the surface of earth is

What is the maximum height attained by a body projected with a velocity equal to one- third of the escape velocity from the surface of the earth? (Radius of the earth=R)

A ball is thrown vertically upwards with a velocity equal to half the escape velocity from the surface of the earth. The ball rises to a height h above the surface of the earth. If the radius of the earth is R, then the ratio h/R is

The escape velocity of a body from the surface of the earth is equal to

If V, R and g denote respectively the escape velocity from the surface of the earth radius of the earth, and acceleration due to gravity, then the correct equation is

A particle is given a velocity (v_(e ))/(sqrt(3)) in a vertically upward direction from the surface of the earth, where v_(e ) is the escape velocity from the surface of the earth. Let the radius of the earth be R. The height of the particle above the surface of the earth at the instant it comes to rest is :

The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

The escape velocity from the surface of the earth is V_(e) . The escape velcotiy from the surface of a planet whose mass and radius are three times those of the earth, will be

NIKITA PUBLICATION-GRAVITATION-Multiple Choice Questions
  1. If the acceleration due to gravity at the surface of the earth is g, t...

    Text Solution

    |

  2. A projectile is fired from the surface of earth of radius R with a vel...

    Text Solution

    |

  3. The escape velocity from the surface of the earth of radius R and dens...

    Text Solution

    |

  4. The radius of a planet is 1/4 of earth’s radius and its acceleration d...

    Text Solution

    |

  5. The escape velocity of a body from the earth is V(e). The escape veloc...

    Text Solution

    |

  6. The radius of the earth is reduced by 1% with mass remaining the same....

    Text Solution

    |

  7. If M be the mass of the earth, R its radius (assumed spherical) and G ...

    Text Solution

    |

  8. An artificial satellite is moving in a circular orbit around the earth...

    Text Solution

    |

  9. A body is projected vertically upwards from the surface of the earth w...

    Text Solution

    |

  10. The escape velocity for a rocket from earth is 11.2 km / sec . Its val...

    Text Solution

    |

  11. The escape velocity from the earth is about 11 km/s. The escape veloci...

    Text Solution

    |

  12. The escape velocity from the surface of earth is V(e). The escape velo...

    Text Solution

    |

  13. The escape velocity for the earth is 11.2 km / sec . The mass of anoth...

    Text Solution

    |

  14. For a satellite escape velocity is 11 km/s . If the satellite is launc...

    Text Solution

    |

  15. The escape velocity on the surface of the earth is 11.2 kms^(-1). If m...

    Text Solution

    |

  16. Given mass of the moon is 1/81 of the mass of the earth and correspond...

    Text Solution

    |

  17. The energy required for a body of mass 1000 kg to escape from the attr...

    Text Solution

    |

  18. The radius in kilometers, to which the present radius of the earth (R ...

    Text Solution

    |

  19. The weight of a body at the centre of the earth is

    Text Solution

    |

  20. If a body is taken from a deep mine to a point at certain height above...

    Text Solution

    |