The radius of a planet is 1/4 of earth’s...

The radius of a planet is `1/4` of earth’s radius and its acceleration due to gravity is double that of earth’s acceleration due to gravity. How many times will the escape velocity at the planet’s surface be as compared to its value on earth’s surface

A

`1//sqrt2`

B

`sqrt2`

C

`2sqrt2`

D

2

Text Solution

Verified by Experts

The correct Answer is:

a

`(v_(e_(2)))/(v_(e_(1)))=sqrt((g_(2)R_(2))/(g_(1)R_(1)))=sqrt((1)/(4)xx2)=(1)/(sqrt2)`.

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