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The escape velocity of a body from the e...

The escape velocity of a body from the earth is `V_(e)`. The escape velocity of a planet whose mass and radius are twice those of the earth is

A

`v_(e)`

B

`2v_(e)`

C

`4v_(e)`

D

`sqrt2v_(e)`

Text Solution

Verified by Experts

The correct Answer is:
a
`(v_(e_(2)))/(v_(e_(1)))=sqrt((M_(2))/(M_(1))(R_(1))/(R_(2)))=sqrt(2xx(1)/(2))=sqrt1=1`
`v_(e_(2))=v_(e)`
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