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The escape velocity for a rocket from ea...

The escape velocity for a rocket from earth is 11.2 km / sec . Its value on a planet where acceleration due to gravity is double that on the earth and diameter of the planet is twice that of earth will be in km / sec

A

11.2

B

5.6

C

22.4

D

53.6

Text Solution

Verified by Experts

The correct Answer is:
c
`(v_(e_(2)))/(v_(e_(1)))=sqrt((g_(2)R_(2))/(g_(1)R_(1)))=sqrt(2xx2)=2`
`v_(e_(2))=2v_(e_(1))`
`=2xx1.2=22.4`
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