The escape velocity for the earth is 11.2 km / sec . The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be

Options

A. 112.0 km/s
B. 5.6 km/s
C. 280 km/s
D. 56.0 km/s

Answer

d

Explanation

`(v_(e_(1)))/(v_(e_(1)))=sqrt((M_(2))/(M_(1))xx(R_(1))/(R_(2)))=sqrt(100xx(1)/(4))`
`v_(e_(2))=5v_(e_(1))`
`=5xx11.2=56.0km//s.`