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The escape velocity on the surface of th...

The escape velocity on the surface of the earth is 11.2 `kms^(-1)`. If mass and radius of a planet is 4 and 2 tims respectively than that of the earth, what is the escape velocity from the planet?

A

11.2 km/s

B

1.112 km/s

C

15.8 km/s

D

22.4 km/s

Text Solution

Verified by Experts

The correct Answer is:
c

`v_(e)=sqrt(2gR)=sqrt((2GM)/(R))=sqrt((2xxGxx4M)/(2R))`
`=sqrt2sqrt((2GM)/(R))=sqrt2=11.2=15.8km//s`
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