The mean radius of earth is R, its angular speed on its own axis is w and the acceleration due to gravity at earth's surface is g. What will be the radius of the orbit of a geostationary satellite

Options

A. `R^(2)g//omega`
B. `R^(2)omega^(2)//g`
C. `Rg//omega`
D. `R^(2)g//omega^(2)`

Answer

d

Explanation

`v_(0)=sqrt((GM)/(r))=sqrt((gR^(2))/(r)) and v_(0) = romega`
`therefore r^(3)=(R^(2)g)/(omega^(2))`