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The angular velocity of rotation of star...

The angular velocity of rotation of star (of mass M and radius R ) at which the matter start to escape from its equator will be

A

`sqrt((2GR)/(M))`

B

`sqrt((2GM)/(R^(3)))`

C

`sqrt((2GM)/(R))`

D

`sqrt(((2GM)^(2))/(R))`

Text Solution

Verified by Experts

The correct Answer is:
b
`v_(e)=sqrt((2GM)/(R))`
`R_(omega)=sqrt((2GM)/(R)) " "therefore omega=sqrt((2GM)/(R^(3)))`
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