A planet has twice the radius but the me...

A planet has twice the radius but the mean density is `1/4` th as compared to earth. What is the ratio of escape velocity from earth to that from the planet

`3:1`

`1:2`

`1:1`

`2:1`

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The correct Answer is:

`(v_(rho_(2)))/(v_(rho_(1)))=(R_(2))/(R_(1))sqrt((rho_(2))/(rho_(1)))=2xxsqrt((1)/(4))=2xx(1)/(2)=1`
`(v_(rho_(2)))/(v_(rho_(1)))=(1)/(1)`

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