The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is
(R = radius of earth)

Options

A. `1//9`
B. `1//16`
C. `1//4`
D. `1//3`

Answer

b

Explanation

`(g_(2))/(g_(1))=((R)/(R+h))^(2)`
`=((R)/(R+3R))^(2)=((R)/(4R))^(2)=(1)/(16)`