The gravitational acceleration on the surface of earth of radius R and mean density `rho` is

Options

A. `(4pi//3)GR^(2)rho`
B. `(4pi^(2)//3)GR^(2)rho`
C. `(2pi^(2)//3)GR^(2)rho`
D. `(4pi//3)GR rho`

Answer

d

Explanation

`g=(GM)/(R^(2))=(Grho(4pi)/(3)R^(3))/(R^(2))`
`g=Grho(4pi)/(3)R=(4pi)/(3)GRrho.`