Home
Class 12
PHYSICS
Let the acceleration due to gravity be g...

Let the acceleration due to gravity be `g_(1)` at a height `h` above the earth's surface `g_(2)` at a depth `d` below the earth's surface. If `g_(1)=g_(2),h lt lt R` and `d lt lt R` then

A

`d=h`

B

`d=(h)/(2)`

C

`d=(h)/(4)`

D

`d=2h`

Text Solution

Verified by Experts

The correct Answer is:
d

`g_(d)=g_(h)`
`g[1-(d)/(R)]=g[1-(2h)/(R)]`
`1-(d)/(R)=1-(2h)/(R)`
`d=2h`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    NIKITA PUBLICATION|Exercise Multiple Choice Questions|458 Videos
  • INTERFERENCE AND DIFFRACTION

    NIKITA PUBLICATION|Exercise MULTPLE CHOICE QUESTIONS|333 Videos

Similar Questions

Explore conceptually related problems

The acceleration due to gravity at a height 1 km above the earth is the same as at a depth d below the surface of earth

The acceleration due to gravity at a height 1km above the earth is the same as at a depth d below the surface of earth. Then :

The acceleration due to gravity at a height h above the surface of the earth has the same value as that at depth d= ____below the earth surface.

Let g_(h) and g_(d) the acceleration due to gravity at height h above the earth s surface and at depth d below the earth surface respecitively if g_(n) = g_(d) then the releation between h and d is

Let g be the acceleration due to gravity on the earth's surface.

The acceleration due to gravity at a depth R//2 below the surface of the earth is

Derive an expression for the acceleration due to gravity at a depth d below the Earth's surface.

The value of the acceleration due to gravity is g_(1) at a height h=(R)/(2) (R=radius of the earth) from the surface of the earth.It is equal to 2g_(1) at a depth d below the surface of the earth.The ratio ((d)/(R)) is equal to:

Find ratio of acceleration due to gravity g at depth d and at height h where d=2h

NIKITA PUBLICATION-GRAVITATION-Multiple Choice Questions
  1. The gravitational acceleration on the surface of earth of radius R and...

    Text Solution

    |

  2. The dimensions of universal gravitational constant are :-

    Text Solution

    |

  3. If the distance between the earth and the sun becomes 1//4th of its pr...

    Text Solution

    |

  4. The densities of two planets are in the ratio of 2 : 3 and their radii...

    Text Solution

    |

  5. The gravitational potential due to the earth is minimum at

    Text Solution

    |

  6. The earth rotates about its own axis, then the value of acceleration d...

    Text Solution

    |

  7. The time period 'T' of the artificial satellite of earth depends on th...

    Text Solution

    |

  8. According the Kepler's law, the areal velocity of a planet around the ...

    Text Solution

    |

  9. If the earth stops rotating, then the weight of an object at the north...

    Text Solution

    |

  10. The escape velocity from the earth is 11 km//s. The escape velocity fr...

    Text Solution

    |

  11. A rocket is launched vertical from the surface of the earth of radius ...

    Text Solution

    |

  12. A communication satellite is revolving around the earth very close to ...

    Text Solution

    |

  13. Imagine a light planet revolving around a very massive star in a circu...

    Text Solution

    |

  14. Calculate angular velocity of the earth so that acceleration due to gr...

    Text Solution

    |

  15. The bulging of the earth at the equator and flattening at the ...

    Text Solution

    |

  16. The bulging of the earth at the equator and flattening at the ...

    Text Solution

    |

  17. The dimensions of universal gravitational constant are :-

    Text Solution

    |

  18. A mass is suspended from a spring having spring constant k is displa...

    Text Solution

    |

  19. A satellite of mass m is in a circular orbit of radius r round the Ear...

    Text Solution

    |

  20. Let the acceleration due to gravity be g(1) at a height h above the ea...

    Text Solution

    |