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The breaking force of wire is 10^(4)N an...

The breaking force of wire is `10^(4)`N and radius is `1xx10^(-3)`m. If the radius is `2xx10^(-3)`m, then the breaking force will be

A

`4xx10^(4)N`

B

`40xx10^(4)N`

C

`0.04xx10^(4)N`

D

`0.4xx10^(4)N`

Text Solution

Verified by Experts

The correct Answer is:
A
`(F_(2))/(F_(1))=((r_(2))/(r_(1)))^(2)=((2xx10^(-3))/(1xx10^(-3)))^(2)=4`
`F_(2)=4F_(1)`
`=4 xx 10^(4)N`.
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