A metal wire can be broken by applying a load of 45 kg wt. Then the force required to break the wire of twice the diameter and the same material is

Options

A. 22.5 kg wt
B. 45 kg wt
C. 90 kg wt
D. 180 kg wt

Answer

D

Explanation

`(F_(2))/(F_(L))=(r_(2)^(2))/(r_(L)^(2))`
`F_(2)= 4xx45=180 kg wt`.