A metal rod undergoes an elastic strain of `0.04%` and the Young's modulus of the material is `3.6xx10^(10)N//m^(2)`. The energy per unit volume stored in the rod in Jule/`m^(3)` is

Options

A. 2592
B. 2880
C. 2222
D. 144

Answer

B

Explanation

`u=(y)/(2)xx("strain")^(2)`
`=(3.6 xx 10^(10))/(2) [4 xx10^(-4)]^(2)`
`=(3.6xx10)/(2) xx 16xx10^(-8) = 28.8xx10^(2)= 28.8xx10^(2)`
`=2880 J//m^(3)`