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A steel wire of length 2.5 m and area of...

A steel wire of length 2.5 m and area of cross section `1.25 mm^(2)`, when it is stretched by a force of 40 N and Y for steel is `2xx10^(11)N//m^(2)`. The extension produced in a steel wire is

A

0.4 mm

B

0.4 cm

C

4 mm

D

4 cm

Text Solution

Verified by Experts

The correct Answer is:
A
`y=(FL)/(Al)`
`therefore l=(40xx2.5)/(2xx10^(11)xx1.25xx10^(-6))=0.4 mm. `
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