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An area of cross-section of rubber strin...

An area of cross-section of rubber string is `2 cm^(2)`. It length is doubled when stretched with a linear force of `2 xx 10^(5)` dynes. The Young's modulus of the rubber in `"dyne/cm"^(2)` will be

A

`4xx10^(5)"dyne"//cm^(2)`

B

`1xx10^(5)"dyne"//cm^(2)`

C

`2xx10^(9)"dyne"/cm^(2)`

D

`1xx10^(9)"dyne"//cm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`y=(FL)/(Al)=(2xx10^(5)xxL)/(2xxL)=10^(5)N//m^(2)`.
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