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A wire of area of cross-section 10^(-6) ...

A wire of area of cross-section `10^(-6) m^(2)` is increased in length by 0.1 %. The tension produced is 1000 N. The Young's modulus of wire is

A

`10^(12)N//m^(2)`

B

`10^(11)N//m^(2)`

C

`10^(7)N//m^(2)`

D

`10^(5)N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`y=(FL)/(Al)=(100xx100)/(10^(-6)xx0.1)=10^(10) N//m^(2)`.
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