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A rubber cord of cross-sectional area 2 ...

A rubber cord of cross-sectional area 2 `cm^(2)` has a length of 1 m. When a tensile force of 10 N is applied, the length of the cord increases by 1 cm. What is the Young's modulus of rubber ?

A

`2xx10^(6)N//m^(2)`

B

`5xx10^(6)N//m^(2)`

C

`0.5 xx 10^(6)N//m^(2)`

D

`0.2xx10^(6)N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`y=(FL)/(Al)=(10xx1)/(2xx10^(-4)xx10^(-2))=5xx10^(6)N//m^(2)`.
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