Two similar wires under the same load yield elongation of `0.1 mm` and `0.05 mm` respectively. If the area of cross-section of the first wire is `4 mm^(2)`, then the area of cross-section of the second wire is

Options

A. `6mm^(2)`
B. `8mm^(2)`
C. `10mm^(2)`
D. `12 mm^(2)`

Answer

B

Explanation

`A_(1)l_(1)=A_(2)l_(2)`
`therefore A_(2) =(A_(1)l_(1))/(l_(2)) = (4xx0.1)/(0.05)=8mm^(2)`