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What should be the weight suspended from...

What should be the weight suspended from the end of a steel wire 2 m in length and w mm in diameter to increase the length by 1 mm ?
`(Y=19xx10^(11)N//m^(2))`

A

30 kg wt

B

305 kg wt

C

32 kg wt

D

33.5 kg wt

Text Solution

Verified by Experts

The correct Answer is:
B
`Y=(F//A)/(l//L)=(MgL)/(pi r^(2)l) " "therefore M=(Y pi r^(2)l)/(gL)`
`=305kg`
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