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A brass wire of length 5 m and cross sec...

A brass wire of length 5 m and cross section area `10^(-6) m^(2)` hung from rigid support with brass weight of volume `10^(-3)m^(3)` hanging from other end. Then the decrease in length of the wire when brass weight is completely immersed in water is,
`(g=10m//s^(2), Y_("brass")=10^(11)N//m^(2), rho_(w)=10^(3)kg//m^(3))`

A

`5xx10^(-4)m`

B

`3xx10^(-4)m`

C

`4xx10^(-4)m`

D

`2xx10^(-2)m`

Text Solution

Verified by Experts

The correct Answer is:
A

`l_(1)-l_(2)=(F_(1)-F_(2))(L)/(Ay)=(v rho gL)/(AY)`
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