An alumminium rod and steel wire of same...

An alumminium rod and steel wire of same length and cross-section are attached end to end. Then compound wire is hung fron a rigid support and load is suspended from the free end. Y for steel is `((20)/(7))` times of aluminium. The ratio of increase in length of steel wire to the aluminium wire is

`7:10`

`20:7`

`10:7`

`7:20`

Text Solution

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The correct Answer is:

`(Y_(L))/(Y_(s))=(l_(s))/(l_(L))`

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