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A wire of cross sectional area 3 mm^(2) ...

A wire of cross sectional area 3 `mm^(2)` is just stretched between two fixed points at a temperature of `20^(@)C` . Then the tension in the wire when the temperature falls to `10^(@)C` is,
`(alpha =1.2 xx 10^(-5) //""^(@)C, Y=2xx10^(11) N//m^(2))`

A

80 N

B

60 N

C

72 N

D

50 N

Text Solution

Verified by Experts

The correct Answer is:
C
`F=Y alpha A Delta t " " because Y=(F//A)/(l//L)`
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